Regards,
Mo’ Kassab

There is one question that no one has answered from my pont of view.
Given the series in a column 2, 4, 5, 6, 8
Return 1,3,7

Is there any query that can achieve this?

2 people asked this already but they didn’t receive an answer.
Thanks in advance.

desc test

desc xparb;
Name Null Type
—– —- —–
SEQ NUMBER(5)

If we issue …
select * from XPARB;
We result with …

SEQ
—
1
2
3
4
6
7
8
9
10
15
16
17
18
19
20

The PL\SQL code to produce the desired output is shown below…

set serveroutput on
declare
k number(6) := 1; — counter to count the number of unused serials [i just used k for Kassab]
cursor crs1 is
select seq,LAG(seq, 1, 0) OVER (ORDER BY seq) AS seq_prev
from xparb; — cursor to fetch all sequences in xparb table
cnt number; — total count of sequences in our e.g. (15) = 1,2,3,4,6,7,8,9,10,15,16,17,18,19,20
v_seq1 number(5);
v_seq2 number(5);
v_diff number(5);
begin
select count(*) into cnt from xparb;
open crs1;
loop
fetch crs1 into v_seq1, v_seq2;
if v_seq1 – v_seq2 1 then
–dbms_output.put_line(v_seq1-1||’,'|| v_seq2);
v_diff := (v_seq1-1)-v_seq2;
–dbms_output.put_line(v_diff);
for i in 1..v_diff loop
dbms_output.put_line(v_seq2+i);
end loop;
end if;
exit when crs1%notfound or crs1%rowcount >= cnt;
end loop;
close crs1;
end;

Hope that helps.

Regards,
Mo’ Kassab

How to find all missing sequencing no like
your no is
1,2,3,4,6,7,8,9,10,15,16,17,18,19,20

required output:
5, 11, 12, 13, 14

Thanks and regards;
Manmohan