Comments on: How to find missing values in a sequence with SQL http://www.xaprb.com/blog/2005/12/06/find-missing-numbers-in-a-sequence-with-sql/ Stay curious! Sat, 30 Aug 2008 04:09:45 +0000 http://wordpress.org/?v=2.2.2 By: charlene http://www.xaprb.com/blog/2005/12/06/find-missing-numbers-in-a-sequence-with-sql/#comment-15024 charlene Wed, 20 Aug 2008 05:37:01 +0000 http://www.xaprb.com/blog/2005/12/06/find-missing-numbers-in-a-sequence-with-sql/#comment-15024 if i want to find gap for example a01, a03, a05? if i want to find gap for example a01, a03, a05?

]]> By: Jay http://www.xaprb.com/blog/2005/12/06/find-missing-numbers-in-a-sequence-with-sql/#comment-14678 Jay Fri, 30 May 2008 17:49:07 +0000 http://www.xaprb.com/blog/2005/12/06/find-missing-numbers-in-a-sequence-with-sql/#comment-14678 Hey this is a great article... but my problem is more complicated I want to find the missing sequences for a 3 column join like Col1 Col2 Col3 1 1 1 1 2 2 1 2 4 2 2 3 2 2 5 3 3 6 3 5 8 And so on... I need to find out all unused permutations in this series.. A query to solve this will be of great help.. Thanks in advance Hey this is a great article… but my problem is more complicated
I want to find the missing sequences for a 3 column join like
Col1 Col2 Col3
1 1 1
1 2 2
1 2 4
2 2 3
2 2 5
3 3 6
3 5 8
And so on… I need to find out all unused permutations in this series.. A query to solve this will be of great help.. Thanks in advance

]]> By: Daniel http://www.xaprb.com/blog/2005/12/06/find-missing-numbers-in-a-sequence-with-sql/#comment-14658 Daniel Tue, 27 May 2008 12:53:35 +0000 http://www.xaprb.com/blog/2005/12/06/find-missing-numbers-in-a-sequence-with-sql/#comment-14658 Greate soution! However I cannot find the gap if it starts with 1. How to solve this? Greate soution! However I cannot find the gap if it starts with 1. How to solve this?

]]> By: Keith http://www.xaprb.com/blog/2005/12/06/find-missing-numbers-in-a-sequence-with-sql/#comment-14536 Keith Fri, 09 May 2008 18:19:32 +0000 http://www.xaprb.com/blog/2005/12/06/find-missing-numbers-in-a-sequence-with-sql/#comment-14536 Thank you! Very helpful in solving a skip in a primary key that used to be auto-assigned. Thank you! Very helpful in solving a skip in a primary key that used to be auto-assigned.

]]> By: Rob http://www.xaprb.com/blog/2005/12/06/find-missing-numbers-in-a-sequence-with-sql/#comment-14457 Rob Fri, 18 Apr 2008 21:04:28 +0000 http://www.xaprb.com/blog/2005/12/06/find-missing-numbers-in-a-sequence-with-sql/#comment-14457 I really enjoyed this article on "How to find missing values in a sequence with SQL". I have a related problem involving finding a missing period of time from a datetime field. For example, I might need to go through a week and find all the times in a variable work day (maybe 8 hours one day and 10 the next) where there is a gap of 5 minutes or more, and keep a sum of the missed time for the day. For example, if two lines were 1/1/2008 01:00:00 AM and 1/1/2008 01:11:00 AM, then that would be a total of 11 minutes that would be added to the total for the day. I want to ignore any gaps less than 5 minutes. Thank you for any help you can give me on this! I really enjoyed this article on “How to find missing values in a sequence with SQL”. I have a related problem involving finding a missing period of time from a datetime field. For example, I might need to go through a week and find all the times in a variable work day (maybe 8 hours one day and 10 the next) where there is a gap of 5 minutes or more, and keep a sum of the missed time for the day. For example, if two lines were 1/1/2008 01:00:00 AM and 1/1/2008 01:11:00 AM, then that would be a total of 11 minutes that would be added to the total for the day. I want to ignore any gaps less than 5 minutes. Thank you for any help you can give me on this!

]]> By: John http://www.xaprb.com/blog/2005/12/06/find-missing-numbers-in-a-sequence-with-sql/#comment-14361 John Fri, 28 Mar 2008 21:11:25 +0000 http://www.xaprb.com/blog/2005/12/06/find-missing-numbers-in-a-sequence-with-sql/#comment-14361 Fantastic! Thanks for putting in the effort to share your work. Fantastic! Thanks for putting in the effort to share your work.

]]> By: Gabor Kiss http://www.xaprb.com/blog/2005/12/06/find-missing-numbers-in-a-sequence-with-sql/#comment-14277 Gabor Kiss Mon, 10 Mar 2008 10:09:32 +0000 http://www.xaprb.com/blog/2005/12/06/find-missing-numbers-in-a-sequence-with-sql/#comment-14277 That is a nice solution. However I cannot understand the semantics of "min(fr.id)". There is no GROUP BY constriction here. I replaced "MIN(fr.id)" with simple "fr.id" and I got the same answer. What did I miss? :-) That is a nice solution. However I cannot understand
the semantics of “min(fr.id)”. There is no GROUP BY
constriction here. I replaced “MIN(fr.id)” with
simple “fr.id” and I got the same answer.
What did I miss? :-)

]]> By: Gabor Kiss http://www.xaprb.com/blog/2005/12/06/find-missing-numbers-in-a-sequence-with-sql/#comment-14276 Gabor Kiss Mon, 10 Mar 2008 10:08:54 +0000 http://www.xaprb.com/blog/2005/12/06/find-missing-numbers-in-a-sequence-with-sql/#comment-14276 select l.id + 1 as start, min(fr.id) - 1 as stop from sequence as l left outer join sequence as r on l.id = r.id - 1 left outer join sequence as fr on l.id select l.id + 1 as start, min(fr.id) - 1 as stop
from sequence as l
left outer join sequence as r on l.id = r.id - 1
left outer join sequence as fr on l.id

]]> By: Bobby Breaux http://www.xaprb.com/blog/2005/12/06/find-missing-numbers-in-a-sequence-with-sql/#comment-14222 Bobby Breaux Sat, 16 Feb 2008 19:04:23 +0000 http://www.xaprb.com/blog/2005/12/06/find-missing-numbers-in-a-sequence-with-sql/#comment-14222 Awesome. Thanks so much for publishing this method of checking for missing rows. Awesome. Thanks so much for publishing this method of checking for missing rows.

]]> By: Cody http://www.xaprb.com/blog/2005/12/06/find-missing-numbers-in-a-sequence-with-sql/#comment-14080 Cody Fri, 14 Dec 2007 15:38:53 +0000 http://www.xaprb.com/blog/2005/12/06/find-missing-numbers-in-a-sequence-with-sql/#comment-14080 Using the example above: select l.id 1 as start, min(fr.id) - 1 as stop from sequence as l left outer join sequence as r on l.id = r.id - 1 left outer join sequence as fr on l.id Using the example above:

select l.id 1 as start, min(fr.id) - 1 as stop
from sequence as l
left outer join sequence as r on l.id = r.id - 1
left outer join sequence as fr on l.id

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