select start, stop from (
select m.id + 1 as start,
(select min(id) – 1 from sequence as x where x.id > m.id) as stop
from sequence as m
left outer join sequence as r on m.id = r.id – 1
where r.id is null
) as x
where stop is not null;

Using the above code I posted earlier on 7-May, I have made some modifications to tune in with your requirements.

Check the code below:

declare
cursor seq_crs is
select to_number(substr(code,-2)) as code from fast order by code;
x number; /*start with minimum number*/
begin
select min(to_number(substr(code,-2))) into x from fast;
for rec in seq_crs loop
while x <= rec.code loop
if x != rec.code then
/* if x doesn't equal rec.code then …*/
dbms_output.put_line(’5G’||to_char(x,’fm0999?));
end if;
x := x+1;
end loop;
end loop;
end;

my result came out to be:
anonymous block completed
5G0010
5G0015
5G0016
5G0017
5G0019

Hope that solved your problem.

Regards,
Kassab

Using the above code I posted earlier on 7-May, I have made some modifications to tune in with your requirements.

Check the code below:

declare
cursor seq_crs is
select to_number(substr(code,-2)) as code from fast order by code;
x number; /*start with minimum number*/
begin
select min(to_number(substr(code,-2))) into x from fast;
for rec in seq_crs loop
while x <= rec.code loop
if x rec.code then
dbms_output.put_line(’5G’||to_char(x,’fm0999?));
end if;
x := x+1;
end loop;
end loop;
end;

my result came out to be:
anonymous block completed
5G0010
5G0015
5G0016
5G0017
5G0019

Hope that solved your problem.

Regards,
Kassab